6x^2+12x-94=0

Solution for 6x^2+12x-94=0 equation:

6x^2+12x-94=0

a = 6; b = 12; c = -94;
Δ = b2-4ac
Δ = 122-4·6·(-94)
Δ = 2400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2400}=\sqrt{400*6}=\sqrt{400}*\sqrt{6}=20\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-20\sqrt{6}}{2*6}=\frac{-12-20\sqrt{6}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+20\sqrt{6}}{2*6}=\frac{-12+20\sqrt{6}}{12}
$